C语言 | Leetcode C语言题解之第338题比特位计数
题目：
题解：
int* countBits(int n, int* returnSize) {int* bits = malloc(sizeof(int) * (n + 1));*returnSize = n + 1;bits[0] = 0;for (int i = 1; i <= n; i++) {bits[i] = bits[i & (i - 1)] + 1;}return bits;
}
题目：
题解：
int* countBits(int n, int* returnSize) {int* bits = malloc(sizeof(int) * (n + 1));*returnSize = n + 1;bits[0] = 0;for (int i = 1; i <= n; i++) {bits[i] = bits[i & (i - 1)] + 1;}return bits;
}