Python | Leetcode Python题解之第401题二进制手表

题目：

题解：

class Solution:def readBinaryWatch(self, turnedOn: int) -> List[str]:ans = list()for i in range(1024):h, m = i >> 6, i & 0x3f   # 用位运算取出高 4 位和低 6 位if h < 12 and m < 60 and bin(i).count("1") == turnedOn:ans.append(f"{h}:{m:02d}")return ans